What is the answer to (5x-3)+(7x-4)=8-(15-11x) ?

The answer to (5x-3)+(7x-4)=8-(15-11x) is x=0

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(5x-3)+(7x-4)=8-(15-11x)

(5 x - 3) + (7 x - 4) = 8 - (15 - 11 x)

x = 0

Solution steps

(5 x - 3) + (7 x - 4) = 8 - (15 - 11 x)

Remove parentheses:

(a) = a

5 x - 3 + 7 x - 4 = 8 - (15 - 11 x)

Group like terms

5 x + 7 x - 3 - 4 = 8 - (15 - 11 x)

Add similar elements:

5 x + 7 x = 12 x

12 x - 3 - 4 = 8 - (15 - 11 x)

Subtract the numbers:

- 3 - 4 = - 7

12 x - 7 = 8 - (15 - 11 x)

Expand

8 - (15 - 11 x) : 11 x - 7

12 x - 7 = 11 x - 7

Move

7

to the right side

12 x = 11 x

Move

11 x

to the left side

x = 0

y, 4 x + y = 12

- \frac{1}{6} + \frac{1}{8} x = - \frac{5}{6}

A, d - 4 h = 3 Q A

k, k 3^{n + 2} - 3 k 3^{n + 1} + 2 k 3^{n} = 3^{n}

y, 3 x + 2 y = - 8

What is the answer to (5x-3)+(7x-4)=8-(15-11x) ?
The answer to (5x-3)+(7x-4)=8-(15-11x) is x=0
Solve for x: (5x-3)+(7x-4)=8-(15-11x)
The solution is x=0