What is ((2n+1)!)/((2n+3)!) ?

The solution to ((2n+1)!)/((2n+3)!) is 1/((2n+2)(2n+3))

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simplify ((2n+1)!)/((2n+3)!)

simplify

\frac{( 2 n + 1 ) !}{( 2 n + 3 ) !}

\frac{1}{( 2 n + 2 ) ( 2 n + 3 )}

Solution steps

\frac{( 2 n + 1 ) !}{( 2 n + 3 ) !}

Cancel the factorials:

\frac{n !}{( n + m ) !} = \frac{1}{( n + 1 ) \cdot ( n + 2 ) \dots ( n + m )}

\frac{( 2 n + 1 ) !}{( 2 n + 3 ) !} = \frac{1}{( 2 n + 2 ) ( 2 n + 3 )}

= \frac{1}{( 2 n + 2 ) ( 2 n + 3 )}

\frac{( 4 - 1 )}{4}

2 y^{3} + 3 y^{2} - 4 y - 6

- 1.2 + (- \frac{3}{5})

(3 + 8 i) (3 - 8 i)

5^{4}

What is ((2n+1)!)/((2n+3)!) ?
The solution to ((2n+1)!)/((2n+3)!) is 1/((2n+2)(2n+3))