What are the solutions to the equation (x^2)/2+(5x)/4 =3 ?

The solutions to the equation (x^2)/2+(5x)/4 =3 are x= 3/2 ,x=-4

Find the zeros of (x^2)/2+(5x)/4 =3

The zeros of (x^2)/2+(5x)/4 =3 are x= 3/2 ,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{x ^{2}}{2} + \frac{5 x}{4} = 3

x = \frac{3}{2}, x = - 4

Decimal Notation

x = 1.5, x = - 4

Solution steps

\frac{x ^{2}}{2} + \frac{5 x}{4} = 3

Find Least Common Multiplier of

2, 4 : 4

Multiply by LCM=

4

\frac{x ^{2}}{2} \cdot 4 + \frac{5 x}{4} \cdot 4 = 3 \cdot 4

Simplify

2 x^{2} + 5 x = 12

Move

12

to the left side

2 x^{2} + 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 12) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 2}, x_{2} = \frac{- 5 - 11}{2 \cdot 2}

x = \frac{- 5 + 11}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 5 - 11}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 4

2^{2 n + 2} - 2^{2 n - 1}

6 x - 31 \leq - 55

y^{4} - x^{8}

2 x - 5 = 5

1 + \frac{0.085}{4}

What are the solutions to the equation (x^2)/2+(5x)/4 =3 ?
The solutions to the equation (x^2)/2+(5x)/4 =3 are x= 3/2 ,x=-4
Find the zeros of (x^2)/2+(5x)/4 =3
The zeros of (x^2)/2+(5x)/4 =3 are x= 3/2 ,x=-4