What are the solutions to the equation 6k^2-42k+72=0 ?

The solutions to the equation 6k^2-42k+72=0 are k=4,k=3

Find the zeros of 6k^2-42k+72=0

The zeros of 6k^2-42k+72=0 are k=4,k=3

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6 k^{2} - 42 k + 72 = 0

k = 4, k = 3

Solution steps

6 k^{2} - 42 k + 72 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 6 \cdot 72}{2 \cdot 6}

(- 42)^{2} - 4 \cdot 6 \cdot 72 = 6

k_{1, 2} = \frac{- ( - 42 ) \pm 6}{2 \cdot 6}

Separate the solutions

k_{1} = \frac{- ( - 42 ) + 6}{2 \cdot 6}, k_{2} = \frac{- ( - 42 ) - 6}{2 \cdot 6}

k = \frac{- ( - 42 ) + 6}{2 \cdot 6} : 4

k = \frac{- ( - 42 ) - 6}{2 \cdot 6} : 3

The solutions to the quadratic equation are:

k = 4, k = 3

36 x^{2} - 121

r^{2} - 10 r + 25 = 1

(6 x - 7) = (4 x + 23)

(- \frac{4}{5})^{0}

\frac{4}{x + 3} \geq 1

What are the solutions to the equation 6k^2-42k+72=0 ?
The solutions to the equation 6k^2-42k+72=0 are k=4,k=3
Find the zeros of 6k^2-42k+72=0
The zeros of 6k^2-42k+72=0 are k=4,k=3