What are the solutions to the equation 8x^2=30+43x ?

The solutions to the equation 8x^2=30+43x are x=6,x=-5/8

Find the zeros of 8x^2=30+43x

The zeros of 8x^2=30+43x are x=6,x=-5/8

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8 x^{2} = 30 + 43 x

x = 6, x = - \frac{5}{8}

Solution steps

8 x^{2} = 30 + 43 x

Move

43 x

to the left side

8 x^{2} - 43 x = 30

Move

30

to the left side

8 x^{2} - 43 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 43 ) \pm ( - 43 ) ^{2} - 4 \cdot 8 ( - 30 )}{2 \cdot 8}

(- 43)^{2} - 4 \cdot 8 (- 30) = 53

x_{1, 2} = \frac{- ( - 43 ) \pm 53}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 43 ) + 53}{2 \cdot 8}, x_{2} = \frac{- ( - 43 ) - 53}{2 \cdot 8}

x = \frac{- ( - 43 ) + 53}{2 \cdot 8} : 6

x = \frac{- ( - 43 ) - 53}{2 \cdot 8} : - \frac{5}{8}

The solutions to the quadratic equation are:

x = 6, x = - \frac{5}{8}

6 = \frac{e}{4} + 2

- 7 x + 5 = - 11 x + 17

4 x^{2} + 9 = 4 x

\frac{1}{4} - x + \frac{3}{6} + x = 0

\frac{3 x - 1}{4} - \frac{2 x + 3}{2} < - 2

What are the solutions to the equation 8x^2=30+43x ?
The solutions to the equation 8x^2=30+43x are x=6,x=-5/8
Find the zeros of 8x^2=30+43x
The zeros of 8x^2=30+43x are x=6,x=-5/8