What is the answer to (x-1)^2+4=(x-3)^2+16 ?

The answer to (x-1)^2+4=(x-3)^2+16 is x=5

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(x-1)^2+4=(x-3)^2+16

(x - 1)^{2} + 4 = (x - 3)^{2} + 16

x = 5

Solution steps

(x - 1)^{2} + 4 = (x - 3)^{2} + 16

Expand

(x - 1)^{2} + 4 : x^{2} - 2 x + 5

Expand

(x - 3)^{2} + 16 : x^{2} - 6 x + 25

x^{2} - 2 x + 5 = x^{2} - 6 x + 25

Move

5

to the right side

x^{2} - 2 x = x^{2} - 6 x + 20

Subtract

x^{2} - 6 x

from both sides

x^{2} - 2 x - (x^{2} - 6 x) = x^{2} - 6 x + 20 - (x^{2} - 6 x)

Simplify

4 x = 20

Divide both sides by

4

x = 5

y, 4 x + 3 y - 12 = 0

y, - x + y = 6

8.35 = n + 1

3 - 2 (x - 3) = 3 (2 x - 5)

y, x + 4 y = - 10

What is the answer to (x-1)^2+4=(x-3)^2+16 ?
The answer to (x-1)^2+4=(x-3)^2+16 is x=5
Solve for x: (x-1)^2+4=(x-3)^2+16
The solution is x=5