What are the solutions to the equation (-1/10-x)(-1/5-x)-3/400 =0 ?

The solutions to the equation (-1/10-x)(-1/5-x)-3/400 =0 are x=-1/20 ,x=-1/4

Find the zeros of (-1/10-x)(-1/5-x)-3/400 =0

The zeros of (-1/10-x)(-1/5-x)-3/400 =0 are x=-1/20 ,x=-1/4

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(- \frac{1}{10} - x) (- \frac{1}{5} - x) - \frac{3}{400} = 0

x = - \frac{1}{20}, x = - \frac{1}{4}

Solution steps

(- \frac{1}{10} - x) (- \frac{1}{5} - x) - \frac{3}{400} = 0

Multiply both sides by

400

400 (- \frac{1}{10} - x) (- \frac{1}{5} - x) - 3 = 0

Expand

400 (- \frac{1}{10} - x) (- \frac{1}{5} - x) - 3 : 400 x^{2} + 120 x + 5

400 x^{2} + 120 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 \cdot 400 \cdot 5}{2 \cdot 400}

12 0^{2} - 4 \cdot 400 \cdot 5 = 80

x_{1, 2} = \frac{- 120 \pm 80}{2 \cdot 400}

Separate the solutions

x_{1} = \frac{- 120 + 80}{2 \cdot 400}, x_{2} = \frac{- 120 - 80}{2 \cdot 400}

x = \frac{- 120 + 80}{2 \cdot 400} : - \frac{1}{20}

x = \frac{- 120 - 80}{2 \cdot 400} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{20}, x = - \frac{1}{4}

13 y - 8 y + 15 \leq - 7 + 32

(- 4 b^{2} + 8 b) + (- 4 b^{3} + 5 b^{2} - 8 b)

8 = - 18 y

n + 4 = 3 n - 16

(\frac{1}{2 x})^{2}

What are the solutions to the equation (-1/10-x)(-1/5-x)-3/400 =0 ?
The solutions to the equation (-1/10-x)(-1/5-x)-3/400 =0 are x=-1/20 ,x=-1/4
Find the zeros of (-1/10-x)(-1/5-x)-3/400 =0
The zeros of (-1/10-x)(-1/5-x)-3/400 =0 are x=-1/20 ,x=-1/4