What are the solutions to the equation 5x-x^2=2x ?

The solutions to the equation 5x-x^2=2x are x=0,x=3

Find the zeros of 5x-x^2=2x

The zeros of 5x-x^2=2x are x=0,x=3

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5 x - x^{2} = 2 x

x = 0, x = 3

Solution steps

5 x - x^{2} = 2 x

Move

2 x

to the left side

- x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 1 )}, x_{2} = \frac{- 3 - 3}{2 ( - 1 )}

x = \frac{- 3 + 3}{2 ( - 1 )} : 0

x = \frac{- 3 - 3}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

4 + 5 p - p^{2} \geq 0

2.7 \cdot 1 0^{- 4} \cdot m \leq 1.62

x^{2} + 12 x + 35 > 0

- 9 + 10

8 x^{2} - 2 x - 10

What are the solutions to the equation 5x-x^2=2x ?
The solutions to the equation 5x-x^2=2x are x=0,x=3
Find the zeros of 5x-x^2=2x
The zeros of 5x-x^2=2x are x=0,x=3