What are the solutions to the equation 2X^2+3X-4=0 ?

The solutions to the equation 2X^2+3X-4=0 are X=(-3+sqrt(41))/4 ,X=(-3-sqrt(41))/4

Find the zeros of 2X^2+3X-4=0

The zeros of 2X^2+3X-4=0 are X=(-3+sqrt(41))/4 ,X=(-3-sqrt(41))/4

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2 X^{2} + 3 X - 4 = 0

X = \frac{- 3 + 41}{4}, X = \frac{- 3 - 41}{4}

Solution steps

2 X^{2} + 3 X - 4 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 4) = 41

X_{1, 2} = \frac{- 3 \pm 41}{2 \cdot 2}

Separate the solutions

X_{1} = \frac{- 3 + 41}{2 \cdot 2}, X_{2} = \frac{- 3 - 41}{2 \cdot 2}

X = \frac{- 3 + 41}{2 \cdot 2} : \frac{- 3 + 41}{4}

X = \frac{- 3 - 41}{2 \cdot 2} : \frac{- 3 - 41}{4}

The solutions to the quadratic equation are:

X = \frac{- 3 + 41}{4}, X = \frac{- 3 - 41}{4}

X^{2} - 1

18 x - 9 < 9 or 2 x - 4 > - 10

2 a^{3} + 7 a^{2} + 6 a

0.25 x + 4.15 \leq 20

ln (2) = 0.08 t

What are the solutions to the equation 2X^2+3X-4=0 ?
The solutions to the equation 2X^2+3X-4=0 are X=(-3+sqrt(41))/4 ,X=(-3-sqrt(41))/4
Find the zeros of 2X^2+3X-4=0
The zeros of 2X^2+3X-4=0 are X=(-3+sqrt(41))/4 ,X=(-3-sqrt(41))/4