What are the solutions to the equation 2X^2+3X-4=0 ?

The solutions to the equation 2X^2+3X-4=0 are X=(-3+sqrt(41))/4 ,X=(-3-sqrt(41))/4

Find the zeros of 2X^2+3X-4=0

The zeros of 2X^2+3X-4=0 are X=(-3+sqrt(41))/4 ,X=(-3-sqrt(41))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 X^{2} + 3 X - 4 = 0

X = \frac{- 3 + 41}{4}, X = \frac{- 3 - 41}{4}

Decimal Notation

X = 0.85078 \dots, X = - 2.35078 \dots

Solution steps

2 X^{2} + 3 X - 4 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 4) = 41

X_{1, 2} = \frac{- 3 \pm 41}{2 \cdot 2}

Separate the solutions

X_{1} = \frac{- 3 + 41}{2 \cdot 2}, X_{2} = \frac{- 3 - 41}{2 \cdot 2}

X = \frac{- 3 + 41}{2 \cdot 2} : \frac{- 3 + 41}{4}

X = \frac{- 3 - 41}{2 \cdot 2} : \frac{- 3 - 41}{4}

The solutions to the quadratic equation are:

X = \frac{- 3 + 41}{4}, X = \frac{- 3 - 41}{4}

X^{2} - 1

18 x - 9 < 9 or 2 x - 4 > - 10

2 a^{3} + 7 a^{2} + 6 a

\frac{( 2 x ^{2} y ^{0} ) ^{3}}{x ^{4}}

0.25 x + 4.15 \leq 20

What are the solutions to the equation 2X^2+3X-4=0 ?
The solutions to the equation 2X^2+3X-4=0 are X=(-3+sqrt(41))/4 ,X=(-3-sqrt(41))/4
Find the zeros of 2X^2+3X-4=0
The zeros of 2X^2+3X-4=0 are X=(-3+sqrt(41))/4 ,X=(-3-sqrt(41))/4