What are the solutions to the equation 2p^2-11p-40=0 ?

The solutions to the equation 2p^2-11p-40=0 are p=8,p=-5/2

Find the zeros of 2p^2-11p-40=0

The zeros of 2p^2-11p-40=0 are p=8,p=-5/2

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2 p^{2} - 11 p - 40 = 0

p = 8, p = - \frac{5}{2}

Decimal Notation

p = 8, p = - 2.5

Solution steps

2 p^{2} - 11 p - 40 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 40 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 40) = 21

p_{1, 2} = \frac{- ( - 11 ) \pm 21}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 11 ) + 21}{2 \cdot 2}, p_{2} = \frac{- ( - 11 ) - 21}{2 \cdot 2}

p = \frac{- ( - 11 ) + 21}{2 \cdot 2} : 8

p = \frac{- ( - 11 ) - 21}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

p = 8, p = - \frac{5}{2}

x - 4 = - 3

80

\frac{c + \frac{64}{c ^{2}}}{1 + \frac{4}{c}}

2 n + 2 \geq - 10

r^{2} - 8 r + 16 = 0

What are the solutions to the equation 2p^2-11p-40=0 ?
The solutions to the equation 2p^2-11p-40=0 are p=8,p=-5/2
Find the zeros of 2p^2-11p-40=0
The zeros of 2p^2-11p-40=0 are p=8,p=-5/2