What is the answer to solvefor a,a(1)^2+b(1)-1=-2 ?

The answer to solvefor a,a(1)^2+b(1)-1=-2 is a=-b-1

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solvefor a,a(1)^2+b(1)-1=-2

solve for

a, a (1)^{2} + b (1) - 1 = - 2

a = - b - 1

Solution steps

a (1)^{2} + b (1) - 1 = - 2

Apply rule

1^{a} = 1

1^{2} = 1

1 \cdot a + 1 \cdot b - 1 = - 2

Multiply:

a \cdot 1 = a

a + 1 \cdot b - 1 = - 2

Multiply:

b \cdot 1 = b

a + b - 1 = - 2

Move

b

to the right side

a - 1 = - 2 - b

Move

1

to the right side

a = - b - 1

x, y = f - 2

x, y = f - 1

8 u - 11 = 6 u - 5

B, 3 q = \frac{B}{g - h}

B, f + B = m

What is the answer to solvefor a,a(1)^2+b(1)-1=-2 ?
The answer to solvefor a,a(1)^2+b(1)-1=-2 is a=-b-1