What are the solutions to the equation 9x^2-6x+226=0 ?

The solutions to the equation 9x^2-6x+226=0 are x= 1/3+5i,x= 1/3-5i

Find the zeros of 9x^2-6x+226=0

The zeros of 9x^2-6x+226=0 are x= 1/3+5i,x= 1/3-5i

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9 x^{2} - 6 x + 226 = 0

x = \frac{1}{3} + 5 i, x = \frac{1}{3} - 5 i

Solution steps

9 x^{2} - 6 x + 226 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 226}{2 \cdot 9}

Simplify

(- 6)^{2} - 4 \cdot 9 \cdot 226 : 90 i

x_{1, 2} = \frac{- ( - 6 ) \pm 90 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 90 i}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 90 i}{2 \cdot 9}

x = \frac{- ( - 6 ) + 90 i}{2 \cdot 9} : \frac{1}{3} + 5 i

x = \frac{- ( - 6 ) - 90 i}{2 \cdot 9} : \frac{1}{3} - 5 i

The solutions to the quadratic equation are:

x = \frac{1}{3} + 5 i, x = \frac{1}{3} - 5 i

- 5 \cdot 8

2^{2} + x - 1 \geq 0

\frac{9}{2 ^{- 1}}

20 x^{2} - 16 x - 48 = 0

\frac{3 x}{x - 7} < - 1

What are the solutions to the equation 9x^2-6x+226=0 ?
The solutions to the equation 9x^2-6x+226=0 are x= 1/3+5i,x= 1/3-5i
Find the zeros of 9x^2-6x+226=0
The zeros of 9x^2-6x+226=0 are x= 1/3+5i,x= 1/3-5i