What are the solutions to the equation 20x^2-16x-48=0 ?

The solutions to the equation 20x^2-16x-48=0 are x=2,x=-6/5

Find the zeros of 20x^2-16x-48=0

The zeros of 20x^2-16x-48=0 are x=2,x=-6/5

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20 x^{2} - 16 x - 48 = 0

x = 2, x = - \frac{6}{5}

Decimal Notation

x = 2, x = - 1.2

Solution steps

20 x^{2} - 16 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 20 ( - 48 )}{2 \cdot 20}

(- 16)^{2} - 4 \cdot 20 (- 48) = 64

x_{1, 2} = \frac{- ( - 16 ) \pm 64}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 64}{2 \cdot 20}, x_{2} = \frac{- ( - 16 ) - 64}{2 \cdot 20}

x = \frac{- ( - 16 ) + 64}{2 \cdot 20} : 2

x = \frac{- ( - 16 ) - 64}{2 \cdot 20} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{6}{5}

\frac{3 x}{x - 7} < - 1

x^{2} - 9 x + 18 > 0

\frac{12 5 ^{2}}{12 5 ^{\frac{4}{3}}}

9 f = \frac{1}{2} (12 f - 2)

3 x + 2 < - 5

What are the solutions to the equation 20x^2-16x-48=0 ?
The solutions to the equation 20x^2-16x-48=0 are x=2,x=-6/5
Find the zeros of 20x^2-16x-48=0
The zeros of 20x^2-16x-48=0 are x=2,x=-6/5