What are the solutions to the equation x^2+20x+103=0 ?

The solutions to the equation x^2+20x+103=0 are x=-10+sqrt(3)i,x=-10-sqrt(3)i

Find the zeros of x^2+20x+103=0

The zeros of x^2+20x+103=0 are x=-10+sqrt(3)i,x=-10-sqrt(3)i

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x^{2} + 20 x + 103 = 0

x = - 10 + 3 i, x = - 10 - 3 i

Solution steps

x^{2} + 20 x + 103 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 103}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 103 : 23 i

x_{1, 2} = \frac{- 20 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 20 - 2 3 i}{2 \cdot 1}

x = \frac{- 20 + 2 3 i}{2 \cdot 1} : - 10 + 3 i

x = \frac{- 20 - 2 3 i}{2 \cdot 1} : - 10 - 3 i

The solutions to the quadratic equation are:

x = - 10 + 3 i, x = - 10 - 3 i

(16 x)^{\frac{1}{2}} (6 x^{\frac{1}{4}})

x^{2} + 2 x - 48 = 0

2 (u + 2) - u = 3 (u - 1) + 9

\frac{x ^{2}}{x ^{2} + x - 6}

5 x^{2} + 5 = 7 x

What are the solutions to the equation x^2+20x+103=0 ?
The solutions to the equation x^2+20x+103=0 are x=-10+sqrt(3)i,x=-10-sqrt(3)i
Find the zeros of x^2+20x+103=0
The zeros of x^2+20x+103=0 are x=-10+sqrt(3)i,x=-10-sqrt(3)i