What is the answer to solvefor x,(xy^2)-1=cy ?

The answer to solvefor x,(xy^2)-1=cy is x=(cy+1)/(y^2);\quad y\ne 0

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solvefor x,(xy^2)-1=cy

solve for

x, (x y^{2}) - 1 = cy

x = \frac{cy + 1}{y ^{2}}; y \neq = 0

Solution steps

(x y^{2}) - 1 = cy

x y^{2} - 1 = cy

Move

1

to the right side

x y^{2} = cy + 1

Divide both sides by

y^{2}; y \neq = 0

x = \frac{cy + 1}{y ^{2}}; y \neq = 0

- 2 (- 4) - (0) = 7

8 x - 18 = 38

x, z = 4 x - y

y, x + 2 y = 13

15 - 3 (t + 5) = - 3 t

What is the answer to solvefor x,(xy^2)-1=cy ?
The answer to solvefor x,(xy^2)-1=cy is x=(cy+1)/(y^2);\quad y\ne 0