What are the solutions to the equation 7x^2+10=18 ?

The solutions to the equation 7x^2+10=18 are x=(2sqrt(2))/(sqrt(7)),x=-(2sqrt(2))/(sqrt(7))

Find the zeros of 7x^2+10=18

The zeros of 7x^2+10=18 are x=(2sqrt(2))/(sqrt(7)),x=-(2sqrt(2))/(sqrt(7))

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7 x^{2} + 10 = 18

x = \frac{2 2}{7}, x = - \frac{2 2}{7}

Decimal Notation

x = 1.06904 \dots, x = - 1.06904 \dots

Solution steps

7 x^{2} + 10 = 18

Move

10

to the right side

7 x^{2} = 8

Divide both sides by

7

x^{2} = \frac{8}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{8}{7}, x = - \frac{8}{7}

\frac{8}{7} = \frac{2 2}{7}

- \frac{8}{7} = - \frac{2 2}{7}

x = \frac{2 2}{7}, x = - \frac{2 2}{7}

R (45) = - 30 x^{2} + 2700 x + 30000

(3 + 5)^{2}

2 (4 x + 1) < 3 (2 x - 3)

y^{2} - 1 = 0

(3 - 5) (3 + 5)

What are the solutions to the equation 7x^2+10=18 ?
The solutions to the equation 7x^2+10=18 are x=(2sqrt(2))/(sqrt(7)),x=-(2sqrt(2))/(sqrt(7))
Find the zeros of 7x^2+10=18
The zeros of 7x^2+10=18 are x=(2sqrt(2))/(sqrt(7)),x=-(2sqrt(2))/(sqrt(7))