What are the solutions to the equation x^2-1x-20=0 ?

The solutions to the equation x^2-1x-20=0 are x=5,x=-4

Find the zeros of x^2-1x-20=0

The zeros of x^2-1x-20=0 are x=5,x=-4

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x^{2} - 1 x - 20 = 0

x = 5, x = - 4

Solution steps

x^{2} - 1 \cdot x - 20 = 0

Refine

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

\frac{2}{3} \cdot 2

6 x^{2} + 15 x

\frac{- 2 - 12 b}{- 2}

\frac{2 0 ^{0.4} - 1}{\frac{1060}{300} - 1}

\frac{1}{2} (4)^{2} - 4

What are the solutions to the equation x^2-1x-20=0 ?
The solutions to the equation x^2-1x-20=0 are x=5,x=-4
Find the zeros of x^2-1x-20=0
The zeros of x^2-1x-20=0 are x=5,x=-4