What is the answer to solvefor a,z=-8-32ba ?

The answer to solvefor a,z=-8-32ba is a=-(z+8)/(32b);\quad b\ne 0

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solvefor a,z=-8-32ba

solve for

a, z = - 8 - 32 ba

a = - \frac{z + 8}{32 b}; b \neq = 0

Solution steps

z = - 8 - 32 ba

Switch sides

- 8 - 32 ba = z

Move

8

to the right side

- 32 ba = z + 8

Divide both sides by

- 32 b; b \neq = 0

a = - \frac{z + 8}{32 b}; b \neq = 0

y, x + 8 y = 8

y, y + x = 7

A, A = 4 h

A, A = 5 h

A, A = 8 h

What is the answer to solvefor a,z=-8-32ba ?
The answer to solvefor a,z=-8-32ba is a=-(z+8)/(32b);\quad b\ne 0