What are the solutions to the equation roots x^2+2x+2 ?

The solutions to the equation roots x^2+2x+2 are x=-1+i,x=-1-i

Find the zeros of roots x^2+2x+2

The zeros of roots x^2+2x+2 are x=-1+i,x=-1-i

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roots

x^{2} + 2 x + 2

x = - 1 + i, x = - 1 - i

Solution steps

x^{2} + 2 x + 2

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

x_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

x = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

x = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

x = - 1 + i, x = - 1 - i

a x^{2} + b x + c

y, x^{2} - y^{2} = 0

\frac{2}{3} x^{2} - 54 = 0

x^{2} - 4 x + 3 = 0

y, x^{2} - 4 x y + y^{2} = 4

What are the solutions to the equation roots x^2+2x+2 ?
The solutions to the equation roots x^2+2x+2 are x=-1+i,x=-1-i
Find the zeros of roots x^2+2x+2
The zeros of roots x^2+2x+2 are x=-1+i,x=-1-i