What are the solutions to the equation q^2+40q+400=36 ?

The solutions to the equation q^2+40q+400=36 are q=-14,q=-26

Find the zeros of q^2+40q+400=36

The zeros of q^2+40q+400=36 are q=-14,q=-26

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q^{2} + 40 q + 400 = 36

q = - 14, q = - 26

Solution steps

q^{2} + 40 q + 400 = 36

Move

36

to the left side

q^{2} + 40 q + 364 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 1 \cdot 364}{2 \cdot 1}

4 0^{2} - 4 \cdot 1 \cdot 364 = 12

q_{1, 2} = \frac{- 40 \pm 12}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 40 + 12}{2 \cdot 1}, q_{2} = \frac{- 40 - 12}{2 \cdot 1}

q = \frac{- 40 + 12}{2 \cdot 1} : - 14

q = \frac{- 40 - 12}{2 \cdot 1} : - 26

The solutions to the quadratic equation are:

q = - 14, q = - 26

\frac{5 ( x - 8 )}{6} = - 7

- \frac{4}{3} m \leq \frac{25}{12}

2 t + 8 = - 10

- x^{2} - x + 12

∣ 4 x + 2 ∣ > 6

What are the solutions to the equation q^2+40q+400=36 ?
The solutions to the equation q^2+40q+400=36 are q=-14,q=-26
Find the zeros of q^2+40q+400=36
The zeros of q^2+40q+400=36 are q=-14,q=-26