What are the solutions to the equation roots x^2+4x+5 ?

The solutions to the equation roots x^2+4x+5 are x=-2+i,x=-2-i

Find the zeros of roots x^2+4x+5

The zeros of roots x^2+4x+5 are x=-2+i,x=-2-i

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roots

x^{2} + 4 x + 5

x = - 2 + i, x = - 2 - i

Solution steps

x^{2} + 4 x + 5

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

x = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

x = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

x = - 2 + i, x = - 2 - i

x, z = x^{2} + y^{2}

x, x^{2} + y^{2} - z^{2} = 1

(x^{2}) + x = 30, x

x, 4 x^{2} + 3 y^{4} = 2 y

(x + 8)^{2} = 1

What are the solutions to the equation roots x^2+4x+5 ?
The solutions to the equation roots x^2+4x+5 are x=-2+i,x=-2-i
Find the zeros of roots x^2+4x+5
The zeros of roots x^2+4x+5 are x=-2+i,x=-2-i