What are the solutions to the equation factor x^2-5x+4=0 ?

The solutions to the equation factor x^2-5x+4=0 are x=1,x=4

Find the zeros of factor x^2-5x+4=0

The zeros of factor x^2-5x+4=0 are x=1,x=4

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x^{2} - 5 x + 4 = 0

x = 1, x = 4

Solution steps

x^{2} - 5 x + 4 = 0

Factor

x^{2} - 5 x + 4 : (x - 1) (x - 4)

(x - 1) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = 1, x = 4

64 x^{2} - (16 a + 4 b) x + ab = 0

14 + 3 h = 5 hh

y, x^{2} + x y + y^{2} = 3

x, x^{2} + y^{2} = a^{2}

y, x^{2} + 5 x y - 4 y^{2} = 10

What are the solutions to the equation factor x^2-5x+4=0 ?
The solutions to the equation factor x^2-5x+4=0 are x=1,x=4
Find the zeros of factor x^2-5x+4=0
The zeros of factor x^2-5x+4=0 are x=1,x=4