What are the solutions to the equation roots x^2+4x+8 ?

The solutions to the equation roots x^2+4x+8 are x=-2+2i,x=-2-2i

Find the zeros of roots x^2+4x+8

The zeros of roots x^2+4x+8 are x=-2+2i,x=-2-2i

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roots

x^{2} + 4 x + 8

x = - 2 + 2 i, x = - 2 - 2 i

Solution steps

x^{2} + 4 x + 8

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 4 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 8 : 4 i

x_{1, 2} = \frac{- 4 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 i}{2 \cdot 1}

x = \frac{- 4 + 4 i}{2 \cdot 1} : - 2 + 2 i

x = \frac{- 4 - 4 i}{2 \cdot 1} : - 2 - 2 i

The solutions to the quadratic equation are:

x = - 2 + 2 i, x = - 2 - 2 i

x^{2} + 6 x + 10 = - x

2 x^{2} - 20 x + 41

\frac{x ^{2} - 4}{3} - \frac{6 - x}{2} = 3

a^{2} + (- 2 a)^{2} = 4 0^{2}

2 x^{2} - 20 x + 41 = 0

What are the solutions to the equation roots x^2+4x+8 ?
The solutions to the equation roots x^2+4x+8 are x=-2+2i,x=-2-2i
Find the zeros of roots x^2+4x+8
The zeros of roots x^2+4x+8 are x=-2+2i,x=-2-2i