What are the solutions to the equation 2x^2+(4b-a)x-2ab=0 ?

The solutions to the equation 2x^2+(4b-a)x-2ab=0 are x= a/2 ,x=-2b

Find the zeros of 2x^2+(4b-a)x-2ab=0

The zeros of 2x^2+(4b-a)x-2ab=0 are x= a/2 ,x=-2b

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2 x^{2} + (4 b - a) x - 2 ab = 0

x = \frac{a}{2}, x = - 2 b

Solution steps

2 x^{2} + (4 b - a) x - 2 ab = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + (4 b - a) x - 2 ba = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 4 b - a ) \pm ( 4 b - a ) ^{2} - 4 \cdot 2 ( - 2 ba )}{2 \cdot 2}

Simplify

(4 b - a)^{2} - 4 \cdot 2 (- 2 ba) : 4 b + a

x_{1, 2} = \frac{- ( 4 b - a ) \pm ( 4 b + a )}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( 4 b - a ) + 4 b + a}{2 \cdot 2}, x_{2} = \frac{- ( 4 b - a ) - ( 4 b + a )}{2 \cdot 2}

x = \frac{- ( 4 b - a ) + 4 b + a}{2 \cdot 2} : \frac{a}{2}

x = \frac{- ( 4 b - a ) - ( 4 b + a )}{2 \cdot 2} : - 2 b

The solutions to the quadratic equation are:

x = \frac{a}{2}, x = - 2 b

x^{2} - 5 x + 6

y, x^{2} + x y + y^{2} = 7

4 - 2 x^{2} = - 14

- x^{2} + x = - 10

12 - 2 x^{2} = - 20

What are the solutions to the equation 2x^2+(4b-a)x-2ab=0 ?
The solutions to the equation 2x^2+(4b-a)x-2ab=0 are x= a/2 ,x=-2b
Find the zeros of 2x^2+(4b-a)x-2ab=0
The zeros of 2x^2+(4b-a)x-2ab=0 are x= a/2 ,x=-2b