What are the solutions to the equation roots s^2+2s+5 ?

The solutions to the equation roots s^2+2s+5 are s=-1+2i,s=-1-2i

Find the zeros of roots s^2+2s+5

The zeros of roots s^2+2s+5 are s=-1+2i,s=-1-2i

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roots

s^{2} + 2 s + 5

s = - 1 + 2 i, s = - 1 - 2 i

Solution steps

s^{2} + 2 s + 5

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 2 s + 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

s_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

s = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

s = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

s = - 1 + 2 i, s = - 1 - 2 i

5 x^{2} - 2 = - 92

2 x^{2} + 12 x + 4

n^{2} - 7 n - 120 = 0

x^{2} - 4 x = 0

x^{2} - 4 x + 13

What are the solutions to the equation roots s^2+2s+5 ?
The solutions to the equation roots s^2+2s+5 are s=-1+2i,s=-1-2i
Find the zeros of roots s^2+2s+5
The zeros of roots s^2+2s+5 are s=-1+2i,s=-1-2i