What are the solutions to the equation solvefor y,x^2-2xy+y^2=0 ?

The solutions to the equation solvefor y,x^2-2xy+y^2=0 are y=x

Find the zeros of solvefor y,x^2-2xy+y^2=0

The zeros of solvefor y,x^2-2xy+y^2=0 are y=x

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solve for

y, x^{2} - 2 x y + y^{2} = 0

y = x

Solution steps

x^{2} - 2 x y + y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 2 x y + x^{2} = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 x ) \pm ( - 2 x ) ^{2} - 4 \cdot 1 \cdot x ^{2}}{2 \cdot 1}

(- 2 x)^{2} - 4 \cdot 1 \cdot x^{2} = 0

y_{1, 2} = \frac{- ( - 2 x ) \pm 0}{2 \cdot 1}

y = \frac{- ( - 2 x )}{2 \cdot 1}

Simplify

\frac{- ( - 2 x )}{2 \cdot 1} : x

y = x

The solution to the quadratic equation is:

y = x

3 p^{2} + 11 p = 4

13 + 3 x^{2} = 16

3 (x^{2} - 2) - 1 = 5

x^{2} - 2 x - 4 = - 2 x

3 x^{2} + 17 x = 6

What are the solutions to the equation solvefor y,x^2-2xy+y^2=0 ?
The solutions to the equation solvefor y,x^2-2xy+y^2=0 are y=x
Find the zeros of solvefor y,x^2-2xy+y^2=0
The zeros of solvefor y,x^2-2xy+y^2=0 are y=x