What are the solutions to the equation 4(3x-8)^2=27 ?

The solutions to the equation 4(3x-8)^2=27 are x=(3sqrt(3)+16)/6 ,x=(-3sqrt(3)+16)/6

Find the zeros of 4(3x-8)^2=27

The zeros of 4(3x-8)^2=27 are x=(3sqrt(3)+16)/6 ,x=(-3sqrt(3)+16)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (3 x - 8)^{2} = 27

x = \frac{3 3 + 16}{6}, x = \frac{- 3 3 + 16}{6}

Decimal Notation

x = 3.53269 \dots, x = 1.80064 \dots

Solution steps

4 (3 x - 8)^{2} = 27

Divide both sides by

4

(3 x - 8)^{2} = \frac{27}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 8 = \frac{27}{4} : x = \frac{3 3 + 16}{6}

Solve

3 x - 8 = - \frac{27}{4} : x = \frac{- 3 3 + 16}{6}

The solutions to the quadratic equation are:

x = \frac{3 3 + 16}{6}, x = \frac{- 3 3 + 16}{6}

s^{2} + s + 1

5 x^{2} - 30 x + 85 = 0

x^{2} + 2 x - 1

x^{2} + 3 = 7

x, z = x^{2} + 4 y^{2}

What are the solutions to the equation 4(3x-8)^2=27 ?
The solutions to the equation 4(3x-8)^2=27 are x=(3sqrt(3)+16)/6 ,x=(-3sqrt(3)+16)/6
Find the zeros of 4(3x-8)^2=27
The zeros of 4(3x-8)^2=27 are x=(3sqrt(3)+16)/6 ,x=(-3sqrt(3)+16)/6