What are the solutions to the equation x^2+10x+1=24 ?

The solutions to the equation x^2+10x+1=24 are x=-5+4sqrt(3),x=-5-4sqrt(3)

Find the zeros of x^2+10x+1=24

The zeros of x^2+10x+1=24 are x=-5+4sqrt(3),x=-5-4sqrt(3)

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x^{2} + 10 x + 1 = 24

x = - 5 + 43, x = - 5 - 43

Decimal Notation

x = 1.92820 \dots, x = - 11.92820 \dots

Solution steps

x^{2} + 10 x + 1 = 24

Move

24

to the left side

x^{2} + 10 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 23) = 83

x_{1, 2} = \frac{- 10 \pm 8 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 8 3}{2 \cdot 1}, x_{2} = \frac{- 10 - 8 3}{2 \cdot 1}

x = \frac{- 10 + 8 3}{2 \cdot 1} : - 5 + 43

x = \frac{- 10 - 8 3}{2 \cdot 1} : - 5 - 43

The solutions to the quadratic equation are:

x = - 5 + 43, x = - 5 - 43

y, x^{2} + y^{2} + 3 x + y + 10 = 0

y, x^{2} y + y^{2} x = - 2

x^{2} + a^{2}

(- 7 - x) (7 - x) + 24 = 0

0.2 x^{2} - 2.2 x - 3.8 = 0

What are the solutions to the equation x^2+10x+1=24 ?
The solutions to the equation x^2+10x+1=24 are x=-5+4sqrt(3),x=-5-4sqrt(3)
Find the zeros of x^2+10x+1=24
The zeros of x^2+10x+1=24 are x=-5+4sqrt(3),x=-5-4sqrt(3)