What are the solutions to the equation (x-3)(x+4)=8 ?

The solutions to the equation (x-3)(x+4)=8 are x=4,x=-5

Find the zeros of (x-3)(x+4)=8

The zeros of (x-3)(x+4)=8 are x=4,x=-5

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(x - 3) (x + 4) = 8

x = 4, x = - 5

Solution steps

(x - 3) (x + 4) = 8

Expand

(x - 3) (x + 4) : x^{2} + x - 12

x^{2} + x - 12 = 8

Move

8

to the left side

x^{2} + x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 1}, x_{2} = \frac{- 1 - 9}{2 \cdot 1}

x = \frac{- 1 + 9}{2 \cdot 1} : 4

x = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

r + 14 = 10.99

\frac{6}{\frac{1}{8}}

4 x^{2} + 2 x - 56

2 x + 9 = 5 x + 4

96 > - 6 (3 n - 7)

What are the solutions to the equation (x-3)(x+4)=8 ?
The solutions to the equation (x-3)(x+4)=8 are x=4,x=-5
Find the zeros of (x-3)(x+4)=8
The zeros of (x-3)(x+4)=8 are x=4,x=-5