What are the solutions to the equation 9x^2+4x-3=0 ?

The solutions to the equation 9x^2+4x-3=0 are x=(-2+sqrt(31))/9 ,x=-(2+sqrt(31))/9

Find the zeros of 9x^2+4x-3=0

The zeros of 9x^2+4x-3=0 are x=(-2+sqrt(31))/9 ,x=-(2+sqrt(31))/9

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9 x^{2} + 4 x - 3 = 0

x = \frac{- 2 + 31}{9}, x = - \frac{2 + 31}{9}

Decimal Notation

x = 0.39641 \dots, x = - 0.84086 \dots

Solution steps

9 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 9 ( - 3 )}{2 \cdot 9}

4^{2} - 4 \cdot 9 (- 3) = 231

x_{1, 2} = \frac{- 4 \pm 2 31}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 4 + 2 31}{2 \cdot 9}, x_{2} = \frac{- 4 - 2 31}{2 \cdot 9}

x = \frac{- 4 + 2 31}{2 \cdot 9} : \frac{- 2 + 31}{9}

x = \frac{- 4 - 2 31}{2 \cdot 9} : - \frac{2 + 31}{9}

The solutions to the quadratic equation are:

x = \frac{- 2 + 31}{9}, x = - \frac{2 + 31}{9}

2 x^{2} + 4 x + 7

t, x = v t + \frac{1}{2} a t^{2}

x^{2} = 7^{8}

y, x^{2} y^{2} + x y = 2

(x + 2)^{2} + 25 = 50

What are the solutions to the equation 9x^2+4x-3=0 ?
The solutions to the equation 9x^2+4x-3=0 are x=(-2+sqrt(31))/9 ,x=-(2+sqrt(31))/9
Find the zeros of 9x^2+4x-3=0
The zeros of 9x^2+4x-3=0 are x=(-2+sqrt(31))/9 ,x=-(2+sqrt(31))/9