What are the solutions to the equation 4(x+2)^2+4=40 ?

The solutions to the equation 4(x+2)^2+4=40 are x=1,x=-5

Find the zeros of 4(x+2)^2+4=40

The zeros of 4(x+2)^2+4=40 are x=1,x=-5

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4 (x + 2)^{2} + 4 = 40

x = 1, x = - 5

Solution steps

4 (x + 2)^{2} + 4 = 40

Move

4

to the right side

4 (x + 2)^{2} = 36

Divide both sides by

4

(x + 2)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 9 : x = 1

Solve

x + 2 = - 9 : x = - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

\frac{( 2 x ^{2} + 7 )}{3} = 13

n^{2} - 2 n + 4 = 0

x^{2} - 4

15 + 3 x^{2} = 24

x^{2} - 2 x + 4

What are the solutions to the equation 4(x+2)^2+4=40 ?
The solutions to the equation 4(x+2)^2+4=40 are x=1,x=-5
Find the zeros of 4(x+2)^2+4=40
The zeros of 4(x+2)^2+4=40 are x=1,x=-5