What are the solutions to the equation -b^2+7*b-10=0 ?

The solutions to the equation -b^2+7*b-10=0 are b=2,b=5

Find the zeros of -b^2+7*b-10=0

The zeros of -b^2+7*b-10=0 are b=2,b=5

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- b^{2} + 7 \cdot b - 10 = 0

b = 2, b = 5

Solution steps

- b^{2} + 7 b - 10 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 10 )}{2 ( - 1 )}

7^{2} - 4 (- 1) (- 10) = 3

b_{1, 2} = \frac{- 7 \pm 3}{2 ( - 1 )}

Separate the solutions

b_{1} = \frac{- 7 + 3}{2 ( - 1 )}, b_{2} = \frac{- 7 - 3}{2 ( - 1 )}

b = \frac{- 7 + 3}{2 ( - 1 )} : 2

b = \frac{- 7 - 3}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

b = 2, b = 5

x^{2} + 2 x + 2 = 0

x^{2} = \frac{5.6}{2.45}

x^{2} - 64 = 0

\frac{- 9 + ( x - 3 ) ^{2}}{- 4} = - 4

x^{2} - x - 2 = 0

What are the solutions to the equation -b^2+7*b-10=0 ?
The solutions to the equation -b^2+7*b-10=0 are b=2,b=5
Find the zeros of -b^2+7*b-10=0
The zeros of -b^2+7*b-10=0 are b=2,b=5