What are the solutions to the equation x^2+16x+63=x+7 ?

The solutions to the equation x^2+16x+63=x+7 are x=-7,x=-8

Find the zeros of x^2+16x+63=x+7

The zeros of x^2+16x+63=x+7 are x=-7,x=-8

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x^{2} + 16 x + 63 = x + 7

x = - 7, x = - 8

Solution steps

x^{2} + 16 x + 63 = x + 7

Move

7

to the left side

x^{2} + 16 x + 56 = x

Move

x

to the left side

x^{2} + 15 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 56 = 1

x_{1, 2} = \frac{- 15 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 1}{2 \cdot 1}, x_{2} = \frac{- 15 - 1}{2 \cdot 1}

x = \frac{- 15 + 1}{2 \cdot 1} : - 7

x = \frac{- 15 - 1}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 7, x = - 8

x^{2} - 14 x + c

7 - x^{2} = 6

X^{2} - 7 X = 18

13 - x^{2} = - 10

20 - x^{2} = 10

What are the solutions to the equation x^2+16x+63=x+7 ?
The solutions to the equation x^2+16x+63=x+7 are x=-7,x=-8
Find the zeros of x^2+16x+63=x+7
The zeros of x^2+16x+63=x+7 are x=-7,x=-8