What are the solutions to the equation 2x^2-16x+33=0 ?

The solutions to the equation 2x^2-16x+33=0 are x=4+i(sqrt(2))/2 ,x=4-i(sqrt(2))/2

Find the zeros of 2x^2-16x+33=0

The zeros of 2x^2-16x+33=0 are x=4+i(sqrt(2))/2 ,x=4-i(sqrt(2))/2

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2 x^{2} - 16 x + 33 = 0

x = 4 + i \frac{2}{2}, x = 4 - i \frac{2}{2}

Solution steps

2 x^{2} - 16 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 33}{2 \cdot 2}

Simplify

(- 16)^{2} - 4 \cdot 2 \cdot 33 : 22 i

x_{1, 2} = \frac{- ( - 16 ) \pm 2 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 2 i}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 2 2 i}{2 \cdot 2}

x = \frac{- ( - 16 ) + 2 2 i}{2 \cdot 2} : 4 + i \frac{2}{2}

x = \frac{- ( - 16 ) - 2 2 i}{2 \cdot 2} : 4 - i \frac{2}{2}

The solutions to the quadratic equation are:

x = 4 + i \frac{2}{2}, x = 4 - i \frac{2}{2}

4 x^{2} + 22 x = 12

x^{2} + 6 x = - 3 x

y, x^{2} + x y + y^{2} = 27

- 4 x^{2} + 8 x + 7 = 0

x^{2} + 4 x + 13

What are the solutions to the equation 2x^2-16x+33=0 ?
The solutions to the equation 2x^2-16x+33=0 are x=4+i(sqrt(2))/2 ,x=4-i(sqrt(2))/2
Find the zeros of 2x^2-16x+33=0
The zeros of 2x^2-16x+33=0 are x=4+i(sqrt(2))/2 ,x=4-i(sqrt(2))/2