What are the solutions to the equation solvefor u,v^2=u^2+2as ?

The solutions to the equation solvefor u,v^2=u^2+2as are u=sqrt(v^2-2as),u=-sqrt(v^2-2as)

Find the zeros of solvefor u,v^2=u^2+2as

The zeros of solvefor u,v^2=u^2+2as are u=sqrt(v^2-2as),u=-sqrt(v^2-2as)

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solve for

u, v^{2} = u^{2} + 2 a s

u = v^{2} - 2 a s, u = - v^{2} - 2 a s

Solution steps

v^{2} = u^{2} + 2 a s

Switch sides

u^{2} + 2 a s = v^{2}

Move

2 a s

to the right side

u^{2} = v^{2} - 2 a s

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = v^{2} - 2 a s, u = - v^{2} - 2 a s

- 9 x^{2} = 30 x + 25

x^{2} + 4 x - 5 = 7

6 - 3 x^{2} = 3

2 (x - 7)^{2} - 31 = 1

x^{2} + 61 = 8 x

What are the solutions to the equation solvefor u,v^2=u^2+2as ?
The solutions to the equation solvefor u,v^2=u^2+2as are u=sqrt(v^2-2as),u=-sqrt(v^2-2as)
Find the zeros of solvefor u,v^2=u^2+2as
The zeros of solvefor u,v^2=u^2+2as are u=sqrt(v^2-2as),u=-sqrt(v^2-2as)