What are the solutions to the equation -7f^2+11f+9=4-3f ?

The solutions to the equation -7f^2+11f+9=4-3f are f=-(-7+2sqrt(21))/7 ,f=(7+2sqrt(21))/7

Find the zeros of -7f^2+11f+9=4-3f

The zeros of -7f^2+11f+9=4-3f are f=-(-7+2sqrt(21))/7 ,f=(7+2sqrt(21))/7

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- 7 f^{2} + 11 f + 9 = 4 - 3 f

f = - \frac{- 7 + 2 21}{7}, f = \frac{7 + 2 21}{7}

Decimal Notation

f = - 0.30930 \dots, f = 2.30930 \dots

Solution steps

- 7 f^{2} + 11 f + 9 = 4 - 3 f

Move

3 f

to the left side

- 7 f^{2} + 14 f + 9 = 4

Move

4

to the left side

- 7 f^{2} + 14 f + 5 = 0

Solve with the quadratic formula

f_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 7 ) \cdot 5}{2 ( - 7 )}

1 4^{2} - 4 (- 7) \cdot 5 = 421

f_{1, 2} = \frac{- 14 \pm 4 21}{2 ( - 7 )}

Separate the solutions

f_{1} = \frac{- 14 + 4 21}{2 ( - 7 )}, f_{2} = \frac{- 14 - 4 21}{2 ( - 7 )}

f = \frac{- 14 + 4 21}{2 ( - 7 )} : - \frac{- 7 + 2 21}{7}

f = \frac{- 14 - 4 21}{2 ( - 7 )} : \frac{7 + 2 21}{7}

The solutions to the quadratic equation are:

f = - \frac{- 7 + 2 21}{7}, f = \frac{7 + 2 21}{7}

4 x^{2} + 61 = 36 x

x, 3 x^{2} + 2 x - 4 = 0

x^{2} + 16 x + 14 = 0

- z^{2} + z = 0

x^{2} - 6 x + 9 = 80

What are the solutions to the equation -7f^2+11f+9=4-3f ?
The solutions to the equation -7f^2+11f+9=4-3f are f=-(-7+2sqrt(21))/7 ,f=(7+2sqrt(21))/7
Find the zeros of -7f^2+11f+9=4-3f
The zeros of -7f^2+11f+9=4-3f are f=-(-7+2sqrt(21))/7 ,f=(7+2sqrt(21))/7