What are the solutions to the equation roots x^2+16x+c ?

The solutions to the equation roots x^2+16x+c are x=-8+sqrt(-c+64),x=-sqrt(-c+64)-8

Find the zeros of roots x^2+16x+c

The zeros of roots x^2+16x+c are x=-8+sqrt(-c+64),x=-sqrt(-c+64)-8

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roots

x^{2} + 16 x + c

x = - 8 + - c + 64, x = - - c + 64 - 8

Solution steps

x^{2} + 16 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 16 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

1 6^{2} - 4 \cdot 1 \cdot c : 2 64 - c

x_{1, 2} = \frac{- 16 \pm 2 64 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 64 - c}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 64 - c}{2 \cdot 1}

x = \frac{- 16 + 2 64 - c}{2 \cdot 1} : - 8 + - c + 64

x = \frac{- 16 - 2 64 - c}{2 \cdot 1} : - - c + 64 - 8

The solutions to the quadratic equation are:

x = - 8 + - c + 64, x = - - c + 64 - 8

(- 5 x + 3) (- x + 6) = 0

\frac{34 x ^{2}}{2 \cdot + 2.6} = 9.8 x

- 3 x^{2} - 18 x - 6 = 0

v, \frac{GM m}{r ^{2}} = m \frac{v ^{2}}{r}

(x + 1)^{2} = 2 x^{2} - 5 x + 11

What are the solutions to the equation roots x^2+16x+c ?
The solutions to the equation roots x^2+16x+c are x=-8+sqrt(-c+64),x=-sqrt(-c+64)-8
Find the zeros of roots x^2+16x+c
The zeros of roots x^2+16x+c are x=-8+sqrt(-c+64),x=-sqrt(-c+64)-8