What are the solutions to the equation x^2-x+5=5 ?

The solutions to the equation x^2-x+5=5 are x=1,x=0

Find the zeros of x^2-x+5=5

The zeros of x^2-x+5=5 are x=1,x=0

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x^{2} - x + 5 = 5

x = 1, x = 0

Solution steps

x^{2} - x + 5 = 5

Move

5

to the left side

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

y, x^{2} + y^{2} = - 1

x, x^{2} + y^{2} + z^{2} = 4

x^{2} - 40 x - 10 = 0

\frac{x ^{2} + 1}{5} - \frac{x + 1}{4} = 1

4 (x + 10)^{2} + 14 = 50

What are the solutions to the equation x^2-x+5=5 ?
The solutions to the equation x^2-x+5=5 are x=1,x=0
Find the zeros of x^2-x+5=5
The zeros of x^2-x+5=5 are x=1,x=0