What are the solutions to the equation roots x^2+14x+c ?

The solutions to the equation roots x^2+14x+c are x=-7+sqrt(-c+49),x=-sqrt(-c+49)-7

Find the zeros of roots x^2+14x+c

The zeros of roots x^2+14x+c are x=-7+sqrt(-c+49),x=-sqrt(-c+49)-7

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roots

x^{2} + 14 x + c

x = - 7 + - c + 49, x = - - c + 49 - 7

Solution steps

x^{2} + 14 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 14 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

1 4^{2} - 4 \cdot 1 \cdot c : 2 49 - c

x_{1, 2} = \frac{- 14 \pm 2 49 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 49 - c}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 49 - c}{2 \cdot 1}

x = \frac{- 14 + 2 49 - c}{2 \cdot 1} : - 7 + - c + 49

x = \frac{- 14 - 2 49 - c}{2 \cdot 1} : - - c + 49 - 7

The solutions to the quadratic equation are:

x = - 7 + - c + 49, x = - - c + 49 - 7

4 (x^{2} - 8) + 3 = - 5

3 x^{2} + 51 = 24 x

3 x^{2} - 18 x - 15 = 0

x^{2} + 30 x = 231

s^{2} + 4 s + 8

What are the solutions to the equation roots x^2+14x+c ?
The solutions to the equation roots x^2+14x+c are x=-7+sqrt(-c+49),x=-sqrt(-c+49)-7
Find the zeros of roots x^2+14x+c
The zeros of roots x^2+14x+c are x=-7+sqrt(-c+49),x=-sqrt(-c+49)-7