What are the solutions to the equation -2x^2+x/3+4=0 ?

The solutions to the equation -2x^2+x/3+4=0 are x=-4/3 ,x= 3/2

Find the zeros of -2x^2+x/3+4=0

The zeros of -2x^2+x/3+4=0 are x=-4/3 ,x= 3/2

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- 2 x^{2} + \frac{x}{3} + 4 = 0

x = - \frac{4}{3}, x = \frac{3}{2}

Decimal Notation

x = - 1.33333 \dots, x = 1.5

Solution steps

- 2 x^{2} + \frac{x}{3} + 4 = 0

Multiply both sides by

3

- 6 x^{2} + x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 6 ) \cdot 12}{2 ( - 6 )}

1^{2} - 4 (- 6) \cdot 12 = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 ( - 6 )}, x_{2} = \frac{- 1 - 17}{2 ( - 6 )}

x = \frac{- 1 + 17}{2 ( - 6 )} : - \frac{4}{3}

x = \frac{- 1 - 17}{2 ( - 6 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = \frac{3}{2}

(- x - 4) (3 x + 3) = 0

x^{2} - 10 x = - x

4 (x - 9)^{2} - 20 = - 4

A = w r^{2} w

4 n^{2} - 2 n = - 4

What are the solutions to the equation -2x^2+x/3+4=0 ?
The solutions to the equation -2x^2+x/3+4=0 are x=-4/3 ,x= 3/2
Find the zeros of -2x^2+x/3+4=0
The zeros of -2x^2+x/3+4=0 are x=-4/3 ,x= 3/2