What are the solutions to the equation 81x^2+36x+4=0 ?

The solutions to the equation 81x^2+36x+4=0 are x=-2/9

Find the zeros of 81x^2+36x+4=0

The zeros of 81x^2+36x+4=0 are x=-2/9

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81 x^{2} + 36 x + 4 = 0

x = - \frac{2}{9}

Decimal Notation

x = - 0.22222 \dots

Solution steps

81 x^{2} + 36 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 81 \cdot 4}{2 \cdot 81}

3 6^{2} - 4 \cdot 81 \cdot 4 = 0

x_{1, 2} = \frac{- 36 \pm 0}{2 \cdot 81}

x = \frac{- 36}{2 \cdot 81}

\frac{- 36}{2 \cdot 81} = - \frac{2}{9}

x = - \frac{2}{9}

The solution to the quadratic equation is:

x = - \frac{2}{9}

3 x^{2} + 23 x + 15

4 - 3600 \cdot + x^{2} = 0

4 x^{2} - 1 = 0

t^{2} - 22 t + 9 = 0

100 x^{2} - 10011 x + 10.011 = 0

What are the solutions to the equation 81x^2+36x+4=0 ?
The solutions to the equation 81x^2+36x+4=0 are x=-2/9
Find the zeros of 81x^2+36x+4=0
The zeros of 81x^2+36x+4=0 are x=-2/9