What are the solutions to the equation 25x^2-196=0 ?

The solutions to the equation 25x^2-196=0 are x= 14/5 ,x=-14/5

Find the zeros of 25x^2-196=0

The zeros of 25x^2-196=0 are x= 14/5 ,x=-14/5

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25 x^{2} - 196 = 0

x = \frac{14}{5}, x = - \frac{14}{5}

Decimal Notation

x = 2.8, x = - 2.8

Solution steps

25 x^{2} - 196 = 0

Move

196

to the right side

25 x^{2} = 196

Divide both sides by

25

x^{2} = \frac{196}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{196}{25}, x = - \frac{196}{25}

\frac{196}{25} = \frac{14}{5}

- \frac{196}{25} = - \frac{14}{5}

x = \frac{14}{5}, x = - \frac{14}{5}

4 (x + 2)^{2} + 13 = 29

y, x^{2} + y^{2} = x y

y, 3 x^{2} + 5 x^{2} y^{2} = 2 y

x^{2} + 2 x - 4 = - 4

4 x^{2} + 5 x = 4 x

What are the solutions to the equation 25x^2-196=0 ?
The solutions to the equation 25x^2-196=0 are x= 14/5 ,x=-14/5
Find the zeros of 25x^2-196=0
The zeros of 25x^2-196=0 are x= 14/5 ,x=-14/5