What are the solutions to the equation x^2-2x-28=-6x+4 ?

The solutions to the equation x^2-2x-28=-6x+4 are x=4,x=-8

Find the zeros of x^2-2x-28=-6x+4

The zeros of x^2-2x-28=-6x+4 are x=4,x=-8

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x^{2} - 2 x - 28 = - 6 x + 4

x = 4, x = - 8

Solution steps

x^{2} - 2 x - 28 = - 6 x + 4

Move

4

to the left side

x^{2} - 2 x - 32 = - 6 x

Move

6 x

to the left side

x^{2} + 4 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 32) = 12

x_{1, 2} = \frac{- 4 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 12}{2 \cdot 1}, x_{2} = \frac{- 4 - 12}{2 \cdot 1}

x = \frac{- 4 + 12}{2 \cdot 1} : 4

x = \frac{- 4 - 12}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 4, x = - 8

4 x^{2} + 32 x = - 68

y, x^{2} - x y^{2} = 2

4 x^{2} + 21 = 4 x

x^{2} + 5 x + 4

x^{2} - 49

What are the solutions to the equation x^2-2x-28=-6x+4 ?
The solutions to the equation x^2-2x-28=-6x+4 are x=4,x=-8
Find the zeros of x^2-2x-28=-6x+4
The zeros of x^2-2x-28=-6x+4 are x=4,x=-8