What are the solutions to the equation 6x^2+x=222 ?

The solutions to the equation 6x^2+x=222 are x=6,x=-37/6

Find the zeros of 6x^2+x=222

The zeros of 6x^2+x=222 are x=6,x=-37/6

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6 x^{2} + x = 222

x = 6, x = - \frac{37}{6}

Decimal Notation

x = 6, x = - 6.16666 \dots

Solution steps

6 x^{2} + x = 222

Move

222

to the left side

6 x^{2} + x - 222 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 222 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 222) = 73

x_{1, 2} = \frac{- 1 \pm 73}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 73}{2 \cdot 6}, x_{2} = \frac{- 1 - 73}{2 \cdot 6}

x = \frac{- 1 + 73}{2 \cdot 6} : 6

x = \frac{- 1 - 73}{2 \cdot 6} : - \frac{37}{6}

The solutions to the quadratic equation are:

x = 6, x = - \frac{37}{6}

h^{2} = 10 h - 3^{2}

x^{2} + 6 x + 8 = 0

4 x^{2} + 18 x - 70 = 0

3 x^{2} + 12 x = 12

4 x^{2} - 4 x + 1 = 0

What are the solutions to the equation 6x^2+x=222 ?
The solutions to the equation 6x^2+x=222 are x=6,x=-37/6
Find the zeros of 6x^2+x=222
The zeros of 6x^2+x=222 are x=6,x=-37/6