What are the solutions to the equation x^2-3x-130=0 ?

The solutions to the equation x^2-3x-130=0 are x=13,x=-10

Find the zeros of x^2-3x-130=0

The zeros of x^2-3x-130=0 are x=13,x=-10

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x^{2} - 3 x - 130 = 0

x = 13, x = - 10

Solution steps

x^{2} - 3 x - 130 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 130 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 130) = 23

x_{1, 2} = \frac{- ( - 3 ) \pm 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 23}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 23}{2 \cdot 1}

x = \frac{- ( - 3 ) + 23}{2 \cdot 1} : 13

x = \frac{- ( - 3 ) - 23}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 13, x = - 10

x, \frac{x ^{2}}{a} + e = t

- 2 x^{2} + 13 x - 20 = 0

4 (x^{2} - 3) + 6 = 10

x^{2} - 9 x = 0

y, y^{2} = \frac{x ^{3}}{4 - x}

What are the solutions to the equation x^2-3x-130=0 ?
The solutions to the equation x^2-3x-130=0 are x=13,x=-10
Find the zeros of x^2-3x-130=0
The zeros of x^2-3x-130=0 are x=13,x=-10