What are the solutions to the equation 0=4x^2+20x+25 ?

The solutions to the equation 0=4x^2+20x+25 are x=-5/2

Find the zeros of 0=4x^2+20x+25

The zeros of 0=4x^2+20x+25 are x=-5/2

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0 = 4 x^{2} + 20 x + 25

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

0 = 4 x^{2} + 20 x + 25

Switch sides

4 x^{2} + 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

x = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

x = - \frac{5}{2}

The solution to the quadratic equation is:

x = - \frac{5}{2}

x, 12320 = 160 x^{2} + 640 x

12 x^{2} - 13 x + 4 = 13 x^{2} - 5 x + 1

x^{2} + 5 x - 310 = 0

a^{2} - 8 a - 12 = 0

y, (x + y)^{3} = x^{3} + y^{3}

What are the solutions to the equation 0=4x^2+20x+25 ?
The solutions to the equation 0=4x^2+20x+25 are x=-5/2
Find the zeros of 0=4x^2+20x+25
The zeros of 0=4x^2+20x+25 are x=-5/2