What are the solutions to the equation roots x^2+28x+c ?

The solutions to the equation roots x^2+28x+c are x=-14+sqrt(-c+196),x=-sqrt(-c+196)-14

Find the zeros of roots x^2+28x+c

The zeros of roots x^2+28x+c are x=-14+sqrt(-c+196),x=-sqrt(-c+196)-14

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roots

x^{2} + 28 x + c

x = - 14 + - c + 196, x = - - c + 196 - 14

Solution steps

x^{2} + 28 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 28 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

2 8^{2} - 4 \cdot 1 \cdot c : 2 196 - c

x_{1, 2} = \frac{- 28 \pm 2 196 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 28 + 2 196 - c}{2 \cdot 1}, x_{2} = \frac{- 28 - 2 196 - c}{2 \cdot 1}

x = \frac{- 28 + 2 196 - c}{2 \cdot 1} : - 14 + - c + 196

x = \frac{- 28 - 2 196 - c}{2 \cdot 1} : - - c + 196 - 14

The solutions to the quadratic equation are:

x = - 14 + - c + 196, x = - - c + 196 - 14

r, α r^{2} + r + α r + 1 = 0

3 x^{2} + 16 = 2 x^{2}

x^{2} + 41 = - 8 x

s^{2} + 2 s + 1

s^{2} + 4 s + 5

What are the solutions to the equation roots x^2+28x+c ?
The solutions to the equation roots x^2+28x+c are x=-14+sqrt(-c+196),x=-sqrt(-c+196)-14
Find the zeros of roots x^2+28x+c
The zeros of roots x^2+28x+c are x=-14+sqrt(-c+196),x=-sqrt(-c+196)-14