What are the solutions to the equation 4w^2+20w+25=0 ?

The solutions to the equation 4w^2+20w+25=0 are w=-5/2

Find the zeros of 4w^2+20w+25=0

The zeros of 4w^2+20w+25=0 are w=-5/2

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4 w^{2} + 20 w + 25 = 0

w = - \frac{5}{2}

Decimal Notation

w = - 2.5

Solution steps

4 w^{2} + 20 w + 25 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

w_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

w = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

w = - \frac{5}{2}

The solution to the quadratic equation is:

w = - \frac{5}{2}

3 x^{2} - 2 x + 4 = 5

x^{2} - (2 x - 21)^{2} = 144

8 x^{2} - 35 = - 18 x

15 - x^{2} = - 14

5 (x + 3)^{2} - 3 = 42

What are the solutions to the equation 4w^2+20w+25=0 ?
The solutions to the equation 4w^2+20w+25=0 are w=-5/2
Find the zeros of 4w^2+20w+25=0
The zeros of 4w^2+20w+25=0 are w=-5/2