What are the solutions to the equation (x-4)^2+4=36 ?

The solutions to the equation (x-4)^2+4=36 are x=4sqrt(2)+4,x=-4sqrt(2)+4

Find the zeros of (x-4)^2+4=36

The zeros of (x-4)^2+4=36 are x=4sqrt(2)+4,x=-4sqrt(2)+4

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(x - 4)^{2} + 4 = 36

x = 42 + 4, x = - 42 + 4

Solution steps

(x - 4)^{2} + 4 = 36

Move

4

to the right side

(x - 4)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 32 : x = 42 + 4

Solve

x - 4 = - 32 : x = - 42 + 4

The solutions to the quadratic equation are:

x = 42 + 4, x = - 42 + 4

\frac{1}{14.5} + \frac{1}{45.5} + \frac{1}{85.5}

12 > - 2 x + 2 > - 4

6 x^{4} - 5 x^{3} - 9 x^{2}

m^{2} + 7 m + 12

\frac{4 x + 9}{1 - 2 x} \geq 3

What are the solutions to the equation (x-4)^2+4=36 ?
The solutions to the equation (x-4)^2+4=36 are x=4sqrt(2)+4,x=-4sqrt(2)+4
Find the zeros of (x-4)^2+4=36
The zeros of (x-4)^2+4=36 are x=4sqrt(2)+4,x=-4sqrt(2)+4