What are the solutions to the equation 2/5 (x+3)^2=5 ?

The solutions to the equation 2/5 (x+3)^2=5 are x= 5/(sqrt(2))-3,x=-5/(sqrt(2))-3

Find the zeros of 2/5 (x+3)^2=5

The zeros of 2/5 (x+3)^2=5 are x= 5/(sqrt(2))-3,x=-5/(sqrt(2))-3

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\frac{2}{5} (x + 3)^{2} = 5

x = \frac{5}{2} - 3, x = - \frac{5}{2} - 3

Decimal Notation

x = 0.53553 \dots, x = - 6.53553 \dots

Solution steps

\frac{2}{5} (x + 3)^{2} = 5

Multiply both sides by

5

2 (x + 3)^{2} = 25

Divide both sides by

2

(x + 3)^{2} = \frac{25}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = \frac{25}{2} : x = \frac{5}{2} - 3

Solve

x + 3 = - \frac{25}{2} : x = - \frac{5}{2} - 3

The solutions to the quadratic equation are:

x = \frac{5}{2} - 3, x = - \frac{5}{2} - 3

0 = 5 x^{2} + 25 x - 65

10 x^{2} + 5 x = 5 x - 8

4 x^{2} - 36 x = - 77

b^{2} + 2 b - 4 = 0

x^{2} - 81 = 0

What are the solutions to the equation 2/5 (x+3)^2=5 ?
The solutions to the equation 2/5 (x+3)^2=5 are x= 5/(sqrt(2))-3,x=-5/(sqrt(2))-3
Find the zeros of 2/5 (x+3)^2=5
The zeros of 2/5 (x+3)^2=5 are x= 5/(sqrt(2))-3,x=-5/(sqrt(2))-3